18x^2-26x-320=0

Solution for 18x^2-26x-320=0 equation:

18x^2-26x-320=0

a = 18; b = -26; c = -320;
Δ = b2-4ac
Δ = -262-4·18·(-320)
Δ = 23716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23716}=154$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-154}{2*18}=\frac{-128}{36}
=-3+5/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+154}{2*18}=\frac{180}{36}
=5
$